3p^2-20p-8=0

Solution for 3p^2-20p-8=0 equation:

3p^2-20p-8=0

a = 3; b = -20; c = -8;
Δ = b2-4ac
Δ = -202-4·3·(-8)
Δ = 496
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{496}=\sqrt{16*31}=\sqrt{16}*\sqrt{31}=4\sqrt{31}$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-4\sqrt{31}}{2*3}=\frac{20-4\sqrt{31}}{6}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+4\sqrt{31}}{2*3}=\frac{20+4\sqrt{31}}{6}
$